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Two vertically suspended springs

For two masses hung in series from springs of natural length

ℓ

, the lower equilibrium spring tension is

m_{2} g

and the upper tension is

(m_{1} + m_{2}) g

. Hence their equilibrium lengths are

L_{2} = ℓ + \frac{m _{2} g}{k _{2}}, L_{1} = ℓ + \frac{( m _{1} + m _{2} ) g}{k _{1}} .

Table of contents 78 1
- Vertical normal modes of two equal suspended masses Two vertically suspended springs 43

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