Splitting field of x cubed minus two ($\mathbb{Q}(\sqrt[3]{2},{\zeta }_3)$)

If $\alpha =\sqrt[3]{2}$ is the positive real root and ${\zeta }_3=e^{2\pi i/3}$, then the roots of $X^3-2$ areTheir splitting field over $\mathbb{Q}$ is $\mathbb{Q}(\alpha ,{\zeta }_3)$.