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Saha ionization equation

Chemical equilibrium for

A^{+} + e^{-} \leftrightarrow A^{0} + γ

gives

\frac{n _{e} n _{A^{+}}}{n _{A^{0}}} = \frac{g _{e} g _{A^{+}}}{g _{A^{0}}} (\frac{2 π m _{e} k _{B} T}{h ^{2}})^{3/2} e^{- I_{A} / (k_{B} T)},

after neglecting the ion--atom mass difference in the translational prefactor.

Table of contents 61 2
- Chemical-potential balance for ionization Saha ionization equation 27
- Hydrogen binding energy Saha ionization equation 13

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