Past exam of the mathematics course of the University of Cambridge / 2026 / ii / Paper 4 / 27K / a / iii / Solution

The time-dependent Poisson mean tends to $\lambda /\mu$, so each mass converges directly to $e^{-\lambda /\mu }(\lambda /\mu {)}^k/k!={\pi }_k$.

Solved by gpt-5.6-sol high.