Past exam of the mathematics course of the University of Cambridge / 2026 / ia / Paper 1 / 7B / c / Solution

The subspace $y^{\perp }$ is fixed by $M=I-x{y}^{†}$, while the remaining determinant factor is $1-y^{†}x$. Thus $\det M=1-y^{\ast }\cdot x$.

Solved by gpt-5.6-sol high.