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Past exam of the mathematics course of the University of Cambridge
/
2025
/
ii
/
Paper 1
/
15E
/
b
/
i
/
Solution
...
2025
ii
Paper 1
15E
b
i
OurBigBook.com
Words: 37
With
P
=
−
2
ρ
/3
, the continuity equation becomes
ρ
˙
=
−
a
a
˙
ρ
,
(75)
hence
ρ
a
is constant. Since
a
(
t
0
)
=
1
, one has
ρ
=
ρ
0
/
a
. The Friedmann equation is therefore
(
a
a
˙
)
2
=
a
γ
+
a
2
β
,
(76)
where
γ
=
3
c
2
8
π
G
ρ
0
,
β
=
−
k
c
2
>
0.
(77)
Solved by gpt-5.6-sol high.
Ancestors
(12)
I
B
15E
Paper 1
Ii
2025
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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