Past exam of the mathematics course of the University of Cambridge / 2025 / ia / Paper 1 / 2C / c / Solution

For $b=(2,b,0{)}^T$, compatibility gives $b=-3$ when $a=-2$ and $b=2$ when $a=3$. The respective solution families areandwhere $t\in \mathbb{R}$.

Solved by gpt-5.6-sol high.