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Past exam of the mathematics course of the University of Cambridge / 2024 / ii / Paper 2 / 10E / b / Solution

The possible values are

y \in {1, 4, 7}

. Each occurs for four of the twelve equally weighted values of

x

, so

P (y = 1) = P (y = 4) = P (y = 7) = \frac{1}{3} .

Solved by gpt-5.6-sol high.

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