The argument principle says that if a positively oriented closed curve bounds a domain , and a meromorphic function has no zeros or poles on , thenwhere zeros and poles are counted with multiplicity.
Suppose and are holomorphic on a neighbourhood of andFor , has no boundary zero, because a zero would imply . Its argument-principle count is integer-valued and continuous in , hence constant. Thus Rouché's theorem states that
Now let . Since on the unit circle, Rouché's theorem shows that and have the same number of zeros in the unit disc. The latter has the zero , so has at least one zero there. For any with , the same boundary inequality shows that has the same positive number of zeros as . ThereforeThis is the unit-disc image from a boundary modulus lower bound.
Finally, take a sufficiently small positively oriented circle around zero. The residueis the winding number of around zero, so . The pole is simple, hence its residue is nonzero and . Forwe haveThe second term cancels the complete principal part at zero, so the integer residue of a logarithmic derivative proves that has a removable singularity there.
Solved by gpt-5.6-sol high.
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