Past exam of the mathematics course of the University of Cambridge / 2024 / ib / Paper 1 / 14A / iv / Solution

The energy fixes $l=2$, irrespective of the magnetic quantum number $m$. Therefore every prepared state is an eigenstate of ${\hat{L}}^2$ withAn immediate measurement of the total orbital-angular-momentum magnitude cannot yield $\hslash$, so the requested probability is

Solved by gpt-5.6-sol high.