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Fix a set and define by recursion on
The recursion theorem defines a function-class uniquely by : for each there is exactly one finite sequence satisfying the displayed recursion through stage . Thus is genuinely functional, and the Axiom schema of replacement applied to the set gives the set .
Now define
It contains every member of . If , then for some ; hence every belongs to
Thus is transitive. If is any transitive set containing every member of , induction gives for every , so . Therefore
is the transitive closure of .
Solved by gpt-5.6-sol high.

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