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Past exam of the mathematics course of the University of Cambridge
/
2023
/
ii
/
Paper 1
/
30K
/
b
/
Solution
...
Past exam of the mathematics course of the University of Cambridge
2023
ii
Paper 1
30K
b
OurBigBook.com
Words: 55
For
0
≤
t
≤
1
,
concavity
of
U
implies
G
(
t
s
1
+
(
1
−
t
)
s
2
)
=
E
[
U
(
t
(
m
+
s
1
Z
)
+
(
1
−
t
)
(
m
+
s
2
Z
)
)
]
≥
tG
(
s
1
)
+
(
1
−
t
)
G
(
s
2
)
,
(312)
so
G
is concave.
Since
E
Z
=
0
,
Jensen inequality
gives
G
(
s
)
=
E
[
U
(
m
+
s
Z
)]
≤
U
(
m
+
s
E
Z
)
=
U
(
m
)
=
G
(
0
)
.
(313)
If
0
≤
s
<
t
, concavity and
s
=
(
1
−
s
/
t
)
0
+
(
s
/
t
)
t
yield
G
(
s
)
≥
(
1
−
t
s
)
G
(
0
)
+
t
s
G
(
t
)
≥
G
(
t
)
.
(314)
Hence
G
is decreasing on
[
0
,
∞
)
; this is
scaled centered risk under concave utility
.
Solved by gpt-5.6-sol high.
Ancestors
(11)
B
30K
Paper 1
Ii
2023
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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