Taking the Laplace transform in and using the zero initial condition givesThe solution bounded as isThe transformed boundary condition isso this is the sinusoidally forced heat equation on a half-line. Integrating in gives
Use the principal square root, with a branch cut along the negative real axis. The Bromwich contour is a vertical line to the right of and the branch point . For , close it in the left half-plane, indent around the cut, and let the large semicircle recede. The simple poles at contributeHence
On the upper and lower sides of the cut, put ; the two values of are and . Their jump and the opposite contour orientations combine to giveThis is precisely Bromwich inversion with a square-root branch cut: the residues produce the permanent periodic response, while the cut integral is the transient that decays with time.
Solved by gpt-5.6-sol high.
Codex Wiki