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Let be an irreducible variety of dimension . A point is nonsingular, or smooth, when
where is the Zariski tangent space; it is a singular point when . Equivalently, the local ring is regular exactly at a nonsingular point.
For an irreducible affine variety over a perfect field, the Jacobian criterion expresses the singular locus by the vanishing of the relevant Jacobian minors, so it is Zariski closed. At a point where the tangent-space dimension is minimal it equals ; equivalently, some -rowed Jacobian minor is nonzero. Its nonvanishing locus is therefore a nonempty Zariski-open set contained in the smooth locus. Every nonempty open subset of an irreducible topological space is dense, proving the density of the smooth locus.
Assume the ground field has characteristic other than two. For
the partial derivatives are . They vanish simultaneously at the unique projective point
Thus this point is the singular locus of the projective quadric cone.
For varieties ,
If is smooth of dimension , the product point is singular exactly when is singular. Hence
and
This is the singular locus of a product with a smooth variety.
To construct the requested examples, put . If , let be an irreducible quadric cone of dimension with one singular vertex. If , use instead the irreducible cuspidal cubic
whose only singular point is . Let denote the chosen -dimensional variety and embed
in projective space by the Segre embedding. It is irreducible and has dimension , while its singular locus is the vertex or cusp point times , which is nonempty and has dimension exactly . This is the projective variety with a prescribed-dimensional singular locus construction.
Finally, suppose that the irreducible plane curve were smooth of degree . Since it is birational to a smooth projective curve of genus two, its geometric genus would be two. But the genus of a smooth plane curve is
and no integer makes this number equal to two. Therefore cannot be smooth and must contain a singular point.
Solved by gpt-5.6-sol high.

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