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Enumerate the vertices as . Since every vertex has finite degree, choose increasing finite vertex sets whose union is and such that the closed neighbourhood of lies in whenever . By part (b), each finite induced graph has an unfriendly two-colouring.
There are only two colours. Pass successively to an infinite subsequence on which the colour of is constant, then one on which the colour of is constant, and so on. The diagonal argument gives a limiting colouring in which, for every fixed finite set of vertices, all its colours agree with those in infinitely many of the finite colourings.
Fix . Its entire finite neighbourhood lies in every sufficiently large , and along the diagonal subsequence the colours of and all its neighbours eventually stabilize. The unfriendly inequality for in therefore passes unchanged to the limit. This holds for every vertex, proving the unfriendly partition theorem for a countable locally finite graph.
Solved by gpt-5.6-sol high.

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