Let Alice and Bob share the Bell stateAlice may measure in the computational basis, remotely preparing Bob's ensemble , or in the Hadamard basis, preparing . Without her outcome, both ensembles have density matrix , as no-signalling requires.
If Bob could clone all four states, the resulting two-qubit ensembles would beandThey are distinguishable: a measurement is perfectly correlated for the first and only equally likely correlated or anticorrelated for the second. Bob could infer Alice's basis choice instantaneously, violating no-signalling. Thus no-signalling implies no-cloning for this set.
Solved by gpt-5.6-sol high.
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