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Past exam of the mathematics course of the University of Cambridge
/
2022
/
ib
/
Paper 3
/
14A
/
b
/
iv
/
Solution
...
2022
ib
Paper 3
14A
b
iv
OurBigBook.com
Words: 36
Use the large-
z
0
expansion
z
0
2
+
R
2
1
=
z
0
1
−
2
z
0
3
R
2
+
O
(
z
0
−
5
)
.
(78)
The first term vanishes by the compatibility condition. For the given
p
, symmetry leaves
∫
p
(
x
,
y
)
(
(
x
−
x
0
)
2
+
(
y
−
y
0
)
2
)
,
d
x
,
d
y
=
−
2
x
0
(
∫
−
π
/2
π
/2
x
sin
x
d
x
)
π
=
−
4
π
x
0
.
(79)
Consequently
u
(
x
0
,
y
0
,
z
0
)
=
−
z
0
3
x
0
+
O
(
z
0
−
5
)
.
(80)
Solved by gpt-5.6-sol high.
Ancestors
(12)
Iv
B
14A
Paper 3
Ib
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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