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Past exam of the mathematics course of the University of Cambridge / 2021 / ii / Paper 2 / 7E / b

Put

t = 1/ z

and

y (t) = w (1/ t)

. Since

w^{'} = - t^{2} y^{'}, w^{''} = t^{4} y^{''} + 2 t^{3} y^{'},

the transformed equation is

y^{''} + (\frac{2}{t} - \frac{p ( 1/ t )}{t ^{2}}) y^{'} + \frac{q ( 1/ t )}{t ^{4}} y = 0.

Table of contents 114 6
- i b 31 1
  - Solution i 31
- ii b 40 1
  - Solution ii 40
- iii b 28 1
  - Solution iii 28

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