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Magnetic-dipole spin-down

If a rigid body's inclined magnetic dipole rotates at angular speed

Ω

, its radiated power is

C Ω^{4}

. Conservation of rotational energy

I Ω^{2} /2

then gives

\dot{Ω} = - \frac{C}{I} Ω^{3}, Ω (t)^{- 2} = Ω_{0}^{- 2} + \frac{2 C}{I} t .

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