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Lorentz reciprocal theorem for Stokes flow
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Viscous fluid flow
Stokes flow
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For two Stokes velocity-stress fields in the same domain,
∫
∂
D
u
(
1
)
⋅
σ
(
2
)
n
d
S
=
∫
∂
D
u
(
2
)
⋅
σ
(
1
)
n
d
S
.
(27)
It follows by integrating the divergence of the corresponding cross-work flux and using symmetry of the Newtonian stress.
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(6)
Stokes flow
Viscous fluid flow
Fluid mechanics
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