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Eigenphase Hadamard-test probability
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Controlled unitary gate
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If
U
∣
ψ
⟩
=
e
2
πi
θ
∣
ψ
⟩
, the ordinary Hadamard test returns ancilla zero with probability
p
0
=
2
1
+
c
o
s
(
2
π
θ
)
=
cos
2
(
π
θ
)
.
(62)
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Hadamard test
Controlled unitary gate
Quantum theory
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